Thursday, November 04, 2004

More on "Blue Cities" v. "Red America"

I noted yesterday that if you take away the six biggest cities in America Bush wins by 7 or 8 million votes, not 3 million. Here's a different way to look at it that puts the question in more focus.

First, consider that, if you take away just three counties: Wayne County, MI (Detroit), Philadelphia, and Cook County, IL (Chicago), Bush would have won Pennsylvania, Michigan and Illinois easily. Absent the inner city Democratic power machines in those three places, Bush wins, not 286-252, but more like 350-180, a landslide. If you take away inner city Milwaukee and inner city Minneapolis, Bush wins Wisconsin and Minnesota too, so it would be 370-160 or so. An even bigger landslide.

Second, sit back and think to yourself.... is voter fraud on a massive scale more likely occuring in the inner city precincts of the south side of Chicago, or is it more likely happening in a small town in rural southern Illinois? Where are people passing out cigarettes in exchange for votes, Milwaukee, or LaCrosse? Where are people registering felons, Philadelphia or Lancaster?

Third, ask yourself, you liberals out there.... would you want to send your kids to public school in any of those inner cities? Would you want to live there and depend on the government there to protect your kids and keep your family safe?

The only reason the Democratic Party can even claim to be a major party is because it has a firm hold on the political machinery in some of the most dysfunctional inner city communities in America. Otherwise, it's probably closer to a 60-40 red-blue split.


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